Use the tables to answer the question.

When trying to solve the quadratic equation x2+4x−5=7
, Jamal and George each provided their work in the tables.
Jamal
Step 1: Set equation = 0 x2+4x−12=0
Step 2: Write quadratic equation as the product of two factors (x+6)(x−2)=0
Step 3: Set each factor equal to 0 x+6=0 and x−2=0
Step 4: Solve each equation x=−6 and x=2
George
Step 1: Set equation = 0 x2+4x−5=7
Step 2: Write quadratic equation as the product of two factors (x+5)(x−1)=7
Step 3: Set each factor equal to 0 x+5=0 and x−1=0
Step 4: Solve each equation x=−5 and x=1

Which student is incorrect? Explain how you know that his solution is inaccurate.

1 answer

To determine which student is incorrect, let's carefully analyze both their approaches to solving the quadratic equation x2+4x5=7.

  1. Rearranging the Equation: Both students correctly start by rearranging the initial equation x2+4x5=7 to set it equal to zero: x2+4x57=0x2+4x12=0(correctly done by Jamal)

  2. Factoring:

    • Jamal's factors: He factored the equation as (x+6)(x2)=0.
    • George's factors: He incorrectly wrote the factors as (x+5)(x1)=0.

Let's verify the correct factors of x2+4x12: To factor x2+4x12, we look for two numbers that multiply to 12 (the constant term) and add up to 4 (the coefficient of x). The numbers 6 and 2 satisfy this requirement: (x+6)(x2)=0 So, Jamal's factoring is correct, and he finds the solutions x=6 and x=2.

Now, we can also verify the factors that George provided for the original equation x2+4x12: George's factors, (x+5)(x1), result in: x21+5x5=x2+4x5 That's incorrect for the equation at hand. Therefore, George's factorization is not valid.

  1. Solutions:
    • Jamal finds the solutions as x=6 and x=2.
    • George finds the incorrect solutions as x=5 and x=1.

Conclusion: George is the incorrect student. His initial factorization of the quadratic x2+4x12=0 was erroneous, leading him to the wrong solutions. The correct roots are obtained from Jamal’s accurate factorization (x+6)(x2)=0, leading to x=6 and x=2.