To expand the expression \( \frac{13}{4}(3x + \frac{3}{4}) \), you can distribute \( \frac{13}{4} \) to both terms inside the parentheses:
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Distributing to \( 3x \): \[ \frac{13}{4} \cdot 3x = \frac{39}{4} x \]
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Distributing to \( \frac{3}{4} \): \[ \frac{13}{4} \cdot \frac{3}{4} = \frac{39}{16} \]
Now, combine the results: \[ \frac{13}{4}(3x + \frac{3}{4}) = \frac{39}{4}x + \frac{39}{16} \]
Thus, the expanded expression is: \[ \frac{39}{4}x + \frac{39}{16} \]