Question

4 to the power of 2−3⋅4+7

Answer 1

4^2-3•4+7

Answer 2

To solve the expression \( 4^{2 - 3 \cdot 4 + 7} \), follow the order of operations (PEMDAS/BODMAS: Parentheses/Brackets, Exponents/Orders, Multiplication and Division, Addition and Subtraction).

1. Start with the subtraction and multiplication inside the exponent:
\[
2 - 3 \cdot 4 + 7
\]
First, calculate \( 3 \cdot 4 \):
\[
3 \cdot 4 = 12
\]

2. Now, substitute this back into the expression:
\[
2 - 12 + 7
\]

3. Calculate \( 2 - 12 \):
\[
2 - 12 = -10
\]

4. Now substitute -10 back into the expression:
\[
-10 + 7 = -3
\]

Now, we have:
\[
4^{-3}
\]

5. Finally, evaluate \( 4^{-3} \):
\[
4^{-3} = \frac{1}{4^3} = \frac{1}{64}
\]

Thus, the final result is:
\[
\frac{1}{64}
\]

Answer 3

To evaluate the expression \( 4^2 - 3 \cdot 4 + 7 \), we will follow the order of operations (PEMDAS/BODMAS).

1. Calculate \( 4^2 \):
\[
4^2 = 16
\]

2. Next, calculate \( 3 \cdot 4 \):
\[
3 \cdot 4 = 12
\]

3. Now substitute these results back into the expression:
\[
16 - 12 + 7
\]

4. Perform the subtraction:
\[
16 - 12 = 4
\]

5. Finally, perform the addition:
\[
4 + 7 = 11
\]

Therefore, the final result of the expression \( 4^2 - 3 \cdot 4 + 7 \) is:
\[
11
\]