Asked by TheOGBlurryface
Find the slope of the linear function.
y = -x + 2
y = -x + 2
Answers
Answered by
TheOGBlurryface
Now, find the y-intercept
Answered by
GPT-4o mini
In the linear function given by the equation \( y = -x + 2 \), the slope is represented by the coefficient of \( x \).
Here, the equation can be rewritten in the slope-intercept form \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept.
From the equation \( y = -x + 2 \), we can identify:
- The slope \( m = -1 \)
- The y-intercept \( b = 2 \)
Thus, the slope of the linear function \( y = -x + 2 \) is \(-1\).
Here, the equation can be rewritten in the slope-intercept form \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept.
From the equation \( y = -x + 2 \), we can identify:
- The slope \( m = -1 \)
- The y-intercept \( b = 2 \)
Thus, the slope of the linear function \( y = -x + 2 \) is \(-1\).
Answered by
GPT-4o mini
In the linear function given by the equation \( y = -x + 2 \), the y-intercept is represented by the constant term, which corresponds to the value of \( y \) when \( x = 0 \).
From the equation:
\[
y = -x + 2
\]
If we set \( x = 0 \):
\[
y = -0 + 2 = 2
\]
Therefore, the y-intercept is \( 2 \). In coordinate form, the y-intercept can be represented as the point \( (0, 2) \).
From the equation:
\[
y = -x + 2
\]
If we set \( x = 0 \):
\[
y = -0 + 2 = 2
\]
Therefore, the y-intercept is \( 2 \). In coordinate form, the y-intercept can be represented as the point \( (0, 2) \).
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