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Original Question
Graph the equation 9−x=32y using slope-intercept form.(1 point) Responses A coordinate plane shows the x-axis ranging from nega...Asked by Ame
Graph the equation 9−x=3/2y
using slope-intercept form.(1 point)
Responses
A) A coordinate plane shows the x-axis ranging from negative 9 to 9 in increments of 1 and the y-axis ranging from 11 to negative 11 in increments of 1. A line with arrows at both ends joins two plotted points. The coordinates of the plotted points are as follows: left parenthesis 0 comma 3 right parenthesis, and left parenthesis 4 comma 2 right parenthesis.
B) A coordinate plane shows the x-axis ranging from negative 9 to 9 in increments of 1 and the y-axis ranging from 11 to negative 11 in increments of 1. A line with arrows at both ends joins two plotted points. The coordinates of the plotted points are as follows: left parenthesis 0 comma negative 3 right parenthesis, and left parenthesis 7 comma negative 1 right parenthesis.
C) An illustration shows a coordinate plane with four quadrants. The x and y axes range from negative 10 to 10 in one unit increments. A downward slanting line is graphed on the coordinate plane. The downward slanting line passes through closed points plotted at left parenthesis 0 comma 6 right parenthesis and left parenthesis 3 comma 4 right parenthesis.
D) A coordinate plane ranges from negative 9 to 9 in unit increments on the x-axis and from 11 to negative 11 in unit increments on the y-axis. A line with arrows at both the ends joins two plotted points and extends beyond. The coordinates of the plotted points are: left parenthesis 0 comma 0 right parenthesis and left parenthesis 2 comma 1 right parenthesis.
using slope-intercept form.(1 point)
Responses
A) A coordinate plane shows the x-axis ranging from negative 9 to 9 in increments of 1 and the y-axis ranging from 11 to negative 11 in increments of 1. A line with arrows at both ends joins two plotted points. The coordinates of the plotted points are as follows: left parenthesis 0 comma 3 right parenthesis, and left parenthesis 4 comma 2 right parenthesis.
B) A coordinate plane shows the x-axis ranging from negative 9 to 9 in increments of 1 and the y-axis ranging from 11 to negative 11 in increments of 1. A line with arrows at both ends joins two plotted points. The coordinates of the plotted points are as follows: left parenthesis 0 comma negative 3 right parenthesis, and left parenthesis 7 comma negative 1 right parenthesis.
C) An illustration shows a coordinate plane with four quadrants. The x and y axes range from negative 10 to 10 in one unit increments. A downward slanting line is graphed on the coordinate plane. The downward slanting line passes through closed points plotted at left parenthesis 0 comma 6 right parenthesis and left parenthesis 3 comma 4 right parenthesis.
D) A coordinate plane ranges from negative 9 to 9 in unit increments on the x-axis and from 11 to negative 11 in unit increments on the y-axis. A line with arrows at both the ends joins two plotted points and extends beyond. The coordinates of the plotted points are: left parenthesis 0 comma 0 right parenthesis and left parenthesis 2 comma 1 right parenthesis.
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To graph the equation \(9 - x = \frac{3}{2}y\), we first need to convert this equation to the slope-intercept form \(y = mx + b\).
Starting from the original equation:
\[
9 - x = \frac{3}{2}y
\]
We can rearrange this to solve for \(y\):
First, isolate \(\frac{3}{2}y\):
\[
\frac{3}{2}y = 9 - x
\]
Next, multiply both sides by \(\frac{2}{3}\) to solve for \(y\):
\[
y = \frac{2}{3}(9 - x)
\]
Distributing the \(\frac{2}{3}\):
\[
y = \frac{2}{3} \cdot 9 - \frac{2}{3}x
\]
\[
y = 6 - \frac{2}{3}x
\]
Now, we have the equation in slope-intercept form:
\[
y = -\frac{2}{3}x + 6
\]
From this form, we can identify that the slope \(m = -\frac{2}{3}\) and the y-intercept \(b = 6\).
To graph this line, we can start by plotting the y-intercept (0, 6) and using the slope to find another point. From (0, 6), going down 2 units and to the right 3 units (since our slope is negative), we find the point (3, 4).
Now let’s look for the responses that fit the description of our line.
- **Checking the options**:
- **A)** Plotted points (0, 3) and (4, 2) do not match.
- **B)** Plotted points (0, -3) and (7, -1) do not match.
- **C)** Points (0, 6) and (3, 4) do match.
- **D)** Plotted points (0, 0) and (2, 1) do not match.
Thus, the correct response is C.
Starting from the original equation:
\[
9 - x = \frac{3}{2}y
\]
We can rearrange this to solve for \(y\):
First, isolate \(\frac{3}{2}y\):
\[
\frac{3}{2}y = 9 - x
\]
Next, multiply both sides by \(\frac{2}{3}\) to solve for \(y\):
\[
y = \frac{2}{3}(9 - x)
\]
Distributing the \(\frac{2}{3}\):
\[
y = \frac{2}{3} \cdot 9 - \frac{2}{3}x
\]
\[
y = 6 - \frac{2}{3}x
\]
Now, we have the equation in slope-intercept form:
\[
y = -\frac{2}{3}x + 6
\]
From this form, we can identify that the slope \(m = -\frac{2}{3}\) and the y-intercept \(b = 6\).
To graph this line, we can start by plotting the y-intercept (0, 6) and using the slope to find another point. From (0, 6), going down 2 units and to the right 3 units (since our slope is negative), we find the point (3, 4).
Now let’s look for the responses that fit the description of our line.
- **Checking the options**:
- **A)** Plotted points (0, 3) and (4, 2) do not match.
- **B)** Plotted points (0, -3) and (7, -1) do not match.
- **C)** Points (0, 6) and (3, 4) do match.
- **D)** Plotted points (0, 0) and (2, 1) do not match.
Thus, the correct response is C.
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