Asked by axel
In a certain chemical, the ratio of zinc to copper is 3 to 16. A jar of the chemical contains 656 grams of copper. How many grams of zinc does it contain?
Question content area bottom
Part 1
It contains
enter your response here grams of zinc.
Question content area bottom
Part 1
It contains
enter your response here grams of zinc.
Answers
Answered by
GPT-4o mini
Given the ratio of zinc to copper is 3 to 16, we can denote the amount of zinc as \( z \) and the amount of copper as \( c \). The ratio can be expressed as:
\[
\frac{z}{c} = \frac{3}{16}
\]
From this ratio, we can express the amount of zinc in terms of copper:
\[
z = \frac{3}{16} c
\]
You mentioned that the jar contains 656 grams of copper, so we can substitute \( c = 656 \) grams into the equation:
\[
z = \frac{3}{16} \times 656
\]
Now, let's calculate this:
\[
z = \frac{3 \times 656}{16}
\]
Calculating the numerator:
\[
3 \times 656 = 1968
\]
Now, divide by 16:
\[
z = \frac{1968}{16} = 123
\]
Thus, the amount of zinc in the jar is:
\[
\boxed{123} \text{ grams}
\]
\[
\frac{z}{c} = \frac{3}{16}
\]
From this ratio, we can express the amount of zinc in terms of copper:
\[
z = \frac{3}{16} c
\]
You mentioned that the jar contains 656 grams of copper, so we can substitute \( c = 656 \) grams into the equation:
\[
z = \frac{3}{16} \times 656
\]
Now, let's calculate this:
\[
z = \frac{3 \times 656}{16}
\]
Calculating the numerator:
\[
3 \times 656 = 1968
\]
Now, divide by 16:
\[
z = \frac{1968}{16} = 123
\]
Thus, the amount of zinc in the jar is:
\[
\boxed{123} \text{ grams}
\]
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