Asked by L**

Calculate the electrode potential of a copper half-call containing 0.05M Cu(NO3).

E^0 Cu2+/Cu = 0.337 V
Answered by DrBob222
E = Eo - (0.0592/n)log[(Cu)/(Cu^+2)]
Substitute 2 for n and 0.05 M for Cu^+2 and 0.337 for Eo. Solve.
Answered by L**
Am I solving for Cu or do I plug a value in for that also?
Answered by DrBob222
Answered above.