Question

A model train travels 2/3 foot in one second. How many feet will it travel in 4 1/5 seconds?
A.
feet
B.
feet
C.
feet
D.
feet

Answer 1

To find out how many feet the model train travels in \(4 \frac{1}{5}\) seconds, we first need to convert \(4 \frac{1}{5}\) to an improper fraction.

1. **Convert \(4 \frac{1}{5}\) to an improper fraction:**

\[
4 \frac{1}{5} = \frac{4 \times 5 + 1}{5} = \frac{20 + 1}{5} = \frac{21}{5}
\]

2. **Calculate the distance traveled:**

The model train travels \(\frac{2}{3}\) foot in one second. Therefore, in \(4 \frac{1}{5}\) seconds, the distance it travels is:

\[
Distance = \text{Speed} \times \text{Time} = \frac{2}{3} \times \frac{21}{5}
\]

3. **Multiply the fractions:**

\[
Distance = \frac{2 \times 21}{3 \times 5} = \frac{42}{15}
\]

4. **Simplify \(\frac{42}{15}\):**

To simplify \(\frac{42}{15}\):

- Find the greatest common divisor (GCD) of 42 and 15, which is 3.

\[
\frac{42 \div 3}{15 \div 3} = \frac{14}{5}
\]

5. **Convert \(\frac{14}{5}\) to a mixed number (if needed):**

Dividing 14 by 5, we get:

\[
14 \div 5 = 2 \text{ remainder } 4
\]
So, \(\frac{14}{5} = 2 \frac{4}{5}\).

Thus, the model train will travel \( \frac{14}{5} \) feet or \( 2 \frac{4}{5} \) feet in \(4 \frac{1}{5}\) seconds.

So the answer is:

A. \( \frac{14}{5} \) feet (or \( 2 \frac{4}{5} \) feet)