Mary wants to rent a hall for a party and she has a budget of $500 for the rental. The hall charges a fee of $200 plus $25 per hour Write an inequality to represent the situation where h is the number of hours mary can rent the hall without exceeding her budget. Then solve to find the maximum number of hours she can afford to rent the hall

1 answer

To represent the situation with an inequality, we can use the following equation based on the total cost of renting the hall:

Cost = Flat fee + (Hourly rate × Number of hours)

In this case, the cost to rent the hall is given by:

\[ \text{Cost} = 200 + 25h \]

where \( h \) is the number of hours Mary rents the hall. Since Mary has a budget of $500, we can set up the inequality:

\[ 200 + 25h \leq 500 \]

Now, we will solve this inequality for \( h \):

  1. Subtract 200 from both sides:

\[ 25h \leq 500 - 200 \]

\[ 25h \leq 300 \]

  1. Now, divide both sides by 25:

\[ h \leq \frac{300}{25} \]

\[ h \leq 12 \]

Thus, the maximum number of hours Mary can rent the hall without exceeding her budget is 12 hours.

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