Rewrite the equation $\frac {5}{2x-8}-1=9$ as two equations joined by "and."(1 point)

$\frac {5}{2x-8}=9$ and $x\neq -8$
$\frac {5}{2x-8}-1=9$ and $x\neq 8$
$\frac {5}{2x-8}-1=9$ and $x\neq -4$
$\frac {5}{2x-8}-1=9$ and $x\neq 4$

3 answers

To rewrite the equation \(\frac{5}{2x-8}-1=9\) as two equations joined by "and", we can isolate the fraction from the equation and also include the restriction that ensures the denominator does not equal zero.

First, we can rearrange the given equation as follows:

\[ \frac{5}{2x-8} = 9 + 1 \]

This simplifies to:

\[ \frac{5}{2x-8} = 10 \]

This leads to one of the two equations, which we can write as:

\[ \frac{5}{2x-8} = 10 \]

Next, we must ensure that the denominator \(2x-8\) is not equal to zero, to avoid division by zero. We solve the inequality:

\[ 2x - 8 \neq 0 \implies 2x \neq 8 \implies x \neq 4 \]

Combining this with the previous equation, we can rewrite our statement as:

\[ \frac{5}{2x-8} = 10 \quad \text{and} \quad x \neq 4 \]

Thus, the correct answer is:

\[\frac {5}{2x-8}=10 \quad \text{and} \quad x\neq 4.\]

Among the provided options, the answer should specifically mention that \(x \neq 4\) for the condition concerning division by zero; hence, the closest alignment depends on the context of the choices given initially. However, as framed, the final answer emphasizes the format of "and" joining the two equations.

Thats not an answer,choose one of the ones i gave you

I apologize for the confusion. Based on the options you provided, the correct answer is:

\(\frac {5}{2x-8}-1=9\) and \(x\neq 4\)

This matches the original equation while including the necessary restriction on \(x\).