Question

Add the linear expressions:  7(n−2)+5(n+4)+3(n+1) .(1 point)
Responses

15n+9
15 n plus 9

3n+3
3 n plus 3

15n
15 n

15n+3

Answer 1

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Answer 2

subtract:%C2%A0%20(2u%E2%88%927y)%E2%88%92(7u+2y)%20.(1%20point)%0AResponses%0A%0A5u%E2%88%929y%0A5%20u%20minus%209%20y%0A%0A%E2%88%925u%E2%88%925y%0Anegative%205%20u%20minus%205%20y%0A%0A%E2%88%925u%E2%88%929y%0Anegative%205%20u%20minus%209%20y%0A%0A5u%E2%88%925y

Answer 3

Simplify 9+3(4a−7)−5a+6 (1 point)
Responses

43a+78
43 a plus 78

43a−78
43 a minus 78

7a−6
7 a minus 6

7a+6

Answer 4

To add the linear expressions \( 7(n-2) + 5(n+4) + 3(n+1) \), we will first distribute the constants across the parentheses:

1. Distributing \( 7 \) in the first term:
\[
7(n - 2) = 7n - 14
\]

2. Distributing \( 5 \) in the second term:
\[
5(n + 4) = 5n + 20
\]

3. Distributing \( 3 \) in the third term:
\[
3(n + 1) = 3n + 3
\]

Now we will combine all of these results:
\[
7n - 14 + 5n + 20 + 3n + 3
\]

Next, we will combine the like terms (the \( n \) terms and the constant terms):
- For the \( n \) terms:
\[
7n + 5n + 3n = 15n
\]

- For the constant terms:
\[
-14 + 20 + 3 = 9
\]

Putting it all together, we get:
\[
15n + 9
\]

So the final answer is:
\[
\boxed{15n + 9}
\]

Answer 5

To subtract the expression \( (j + 2) - 2(3 - 9j) \), we first start by distributing the \(-2\) across the second term:

1. Distributing \(-2\) in the second term:
\[
-2(3 - 9j) = -2 \cdot 3 + (-2) \cdot (-9j) = -6 + 18j
\]

Now we rewrite the original expression incorporating this distribution:
\[
(j + 2) - (6 - 18j)
\]

Now, we can rewrite it without the parentheses:
\[
j + 2 - 6 + 18j
\]

Next, we combine the like terms:
- For the \(j\) terms:
\[
j + 18j = 19j
\]

- For the constant terms:
\[
2 - 6 = -4
\]

Putting these together, we get:
\[
19j - 4
\]

Thus, the final answer is:
\[
\boxed{19j - 4}
\]

Answer 6

To subtract the expression \( (2u - 7y) - (7u + 2y) \), we will first distribute the negative sign across the second term:

1. Rewrite the expression:
\[
(2u - 7y) - (7u + 2y) = 2u - 7y - 7u - 2y
\]

Now we combine like terms:
- Combine the \(u\) terms:
\[
2u - 7u = -5u
\]

- Combine the \(y\) terms:
\[
-7y - 2y = -9y
\]

Putting it all together, we have:
\[
-5u - 9y
\]

Thus, the final answer is:
\[
\boxed{-5u - 9y}
\]

Answer 7

To simplify the expression \( 9 + 3(4a - 7) - 5a + 6 \), we will follow these steps:

1. **Distribute the 3** in the term \( 3(4a - 7) \):
\[
3(4a - 7) = 12a - 21
\]

2. **Substitute** this back into the expression:
\[
9 + (12a - 21) - 5a + 6
\]

3. **Combine like terms**:
- Combine the \(a\) terms:
\[
12a - 5a = 7a
\]
- Combine the constant terms:
\[
9 - 21 + 6 = -12 + 6 = -6
\]

4. **Put everything together**:
\[
7a - 6
\]

So the final simplified expression is:
\[
\boxed{7a - 6}
\]