Asked by Anonymous
What mass, in grams, of sodium hydroxide (NaOH) is produced if 20 grams of sodium metal(Na) reacts with excess water?
Answers
Answered by
DrBob222
1. Write the equation and balance it.
2. Convert 20 g Na metal to moles. mols = grams/molar mass.
3. Using the coefficients in the balanced equation, convert moles Na metal to mols NaOH.
4. Now convert moles NaOH to grams. g = moles x molar mass.
2. Convert 20 g Na metal to moles. mols = grams/molar mass.
3. Using the coefficients in the balanced equation, convert moles Na metal to mols NaOH.
4. Now convert moles NaOH to grams. g = moles x molar mass.
Answered by
Nic
2Na + S --> Na2S
20g Na x (1 mole Na)/(23g Na) = 0.87 mol Na
0.87 mole Na x (1 mol Na2S)/(2 mol Na) x (55.1g Na2S)/(1 mol Na2S)
=23.97g Na2S
20g Na x (1 mole Na)/(23g Na) = 0.87 mol Na
0.87 mole Na x (1 mol Na2S)/(2 mol Na) x (55.1g Na2S)/(1 mol Na2S)
=23.97g Na2S
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