Subtract 4.66×10−5−7.34×10−7

Question

(1 point)
Responses

2.68×102
2.68 times 10 squared

4.5866×10−5
4.5866 times 10 superscript negative 5 baseline

−2.68×102
negative 2.68 times 10 squared

−4.5866×10−5

Answer 1

To subtract \(4.66 \times 10^{-5}\) and \(7.34 \times 10^{-7}\), we first need to express both numbers with the same exponent.

1. Rewrite \(4.66 \times 10^{-5}\) to have the same exponent as \(7.34 \times 10^{-7}\):

\[ 4.66 \times 10^{-5} = 4.66 \times 10^{-5} \times \frac{100}{100} = 4.66 \times 10^{-5} \times 10^{-2} = 4.66 \times 10^{-7} \times 10^{2} = 466 \times 10^{-7} \]

2. Now we can subtract:

\[ 4.66 \times 10^{-5} - 7.34 \times 10^{-7} = 466 \times 10^{-7} - 7.34 \times 10^{-7} \]

3. Performing the subtraction:

\[ 466 - 7.34 = 458.66 \]

4. Putting the result back in scientific notation:

\[ 458.66 \times 10^{-7} = 4.5866 \times 10^{-5} \]

Thus, the final answer is:

4.5866×10−5

Answer 2

The U.S. national debt was $2.9617×1013
in 2021 and $3.98×1011
in 1971. Find how much the debt increased in the 50-year period. (1 point)
Responses

$2.9219×1011
2.9219 dollars times 10 superscript 11 baseline

$2.9219×1013
2.9219 dollars times 10 superscript 13 baseline

$1.0183×1024
1.0183 dollars times 10 superscript 24 baseline

$3.0015×1013
3.0015 dollars times 10 superscript 13 baseline

Answer 3

To find how much the U.S. national debt increased from 1971 to 2021, we need to subtract the debt in 1971 from the debt in 2021.

Given:

• National debt in 2021: \(2.9617 \times 10^{13}\)
• National debt in 1971: \(3.98 \times 10^{11}\)

First, we rewrite \(3.98 \times 10^{11}\) in terms of \(10^{13}\):

\[ 3.98 \times 10^{11} = 0.0398 \times 10^{13} \]

Now we can perform the subtraction:

\[ 2.9617 \times 10^{13} - 0.0398 \times 10^{13} = (2.9617 - 0.0398) \times 10^{13} \]

Calculating the subtraction:

\[ 2.9617 - 0.0398 = 2.9219 \]

Thus, the increase in national debt is:

\[ 2.9219 \times 10^{13} \]

So, the final answer is:

$2.9219 \times 10^{13}

Answer 4

The size of a hydrogen atom is about 1.2×10−10
m across. The size of an oxygen atom is 0.000000000152 m across. What is the difference between the sizes of these atoms in scientific notation?(1 point)
Responses

3.2 ×10−10
m
3.2 times 10 superscript negative 10 baseline m

3.2×10−11
m
3.2 times 10 superscript negative 11 baseline m

3.2×10−9
m
3.2 times 10 superscript negative 9 baseline m

2.72×10−10
m

Answer 5

To find the difference in size between a hydrogen atom and an oxygen atom, we need to express both sizes in scientific notation and then subtract.

Given:

• Size of a hydrogen atom: \(1.2 \times 10^{-10} , m\)
• Size of an oxygen atom: \(0.000000000152 , m = 1.52 \times 10^{-10} , m\)

Now we can proceed with the subtraction:

\[ 1.2 \times 10^{-10} , m - 1.52 \times 10^{-10} , m \]

Since both numbers have the same exponent, we can directly subtract the coefficients:

\[ 1.2 - 1.52 = -0.32 \]

Now, we need to express \(-0.32\) in scientific notation:

\[ -0.32 = -3.2 \times 10^{-1} \]

However, we need to adjust it to match the exponent of \(10^{-10}\):

\[ -0.32 \times 10^{-10} = -3.2 \times 10^{-11} \]

Thus, the final difference between the sizes of the hydrogen and oxygen atoms is:

3.2 × 10^{-11} m (which would be implied as a positive difference in magnitude regardless of the atom size.)

Answer 6

Platelets and red blood cells are components of the blood. A typical platelet and red blood cell have diameters of approximately 2.33×10−6
m and 0.0000075 m, respectively. Which blood component has a bigger diameter, and approximately by how much?(1 point)
Responses

A platelet has a bigger diameter than a red blood cell by 9.83×10−6
m.
A platelet has a bigger diameter than a red blood cell by 9.83 times 10 superscript negative 6 baseline m.

A red blood cell has a bigger diameter than a platelet by 5.17×10−6
m.
A red blood cell has a bigger diameter than a platelet by 5.17 times 10 superscript negative 6 baseline m.

A red blood cell has a bigger diameter than a platelet by 9.83×10−6
m.
A red blood cell has a bigger diameter than a platelet by 9.83 times 10 superscript negative 6 baseline m.

A platelet has a bigger diameter than a red blood cell by 5.17×10−6
m.

Answer 7

To compare the diameters of platelets and red blood cells, we'll first express both sizes in scientific notation.

Given:

• Diameter of a platelet: \(2.33 \times 10^{-6} , m\)
• Diameter of a red blood cell: \(0.0000075 , m = 7.5 \times 10^{-6} , m\)

Now, we can compare the two values:

1. Comparing the sizes:
   • Diameter of platelet: \(2.33 \times 10^{-6} , m\)
   • Diameter of red blood cell: \(7.5 \times 10^{-6} , m\)

We see that \(7.5 \times 10^{-6} > 2.33 \times 10^{-6}\), so a red blood cell has a bigger diameter than a platelet.

2. Calculating the difference: \[ 7.5 \times 10^{-6} , m - 2.33 \times 10^{-6} , m \]

Calculating the difference in coefficients: \[ 7.5 - 2.33 = 5.17 \]

Thus, the difference in diameter is: \[ 5.17 \times 10^{-6} , m \]

So the final answer is:

A red blood cell has a bigger diameter than a platelet by \(5.17 \times 10^{-6} , m\).

Answer 8

China and India are the most populous countries in the world. China’s population is approximately 1.45×109
, while India’s population is approximately 1,400,000,000. How many more people live in China than in India?(1 point)
Responses

5×1010
5 times 10 superscript 10 baseline

5×109
5 times 10 superscript 9 baseline

5×107
5 times 10 superscript 7 baseline

5×108

Answer 9

To find how many more people live in China than in India, we will first convert both populations into the same form (scientific notation).

Given:

• China’s population: \(1.45 \times 10^9\)
• India’s population: \(1,400,000,000\), which can be written in scientific notation as \(1.4 \times 10^9\).

Now, let's subtract India's population from China's population:

\[ 1.45 \times 10^9 - 1.4 \times 10^9 \]

Calculating the difference in coefficients:

\[ 1.45 - 1.4 = 0.05 \]

So, the difference in population will be:

\[ 0.05 \times 10^9 \]

To express \(0.05\) in scientific notation, it can be rewritten as:

\[ 5.0 \times 10^{-2} \]

Thus, we can re-adjust our expression:

\[ 0.05 \times 10^9 = 5.0 \times 10^{-2} \times 10^9 = 5.0 \times 10^{7} \]

Hence:

\[ 5.0 \times 10^7 \]

Therefore, the final answer is:

5×10^7 (5 times 10 superscript 7 baseline)