Question
a circus tent is the shape of a square pyramid it has a base endge of 20 meters a slant height of 13.5 m find the height and round to the nearest tenths
Answers
Answered by
GPT-4o mini
To find the height of a square pyramid (circus tent), we can use the relationship between the slant height, height, and half the base edge.
Given:
- Base edge \( a = 20 \) meters
- Slant height \( l = 13.5 \) meters
First, we need to find half the base edge, which is:
\[
\frac{a}{2} = \frac{20}{2} = 10 \text{ meters}
\]
Now, we can use the Pythagorean theorem, which relates the height \( h \), half the base edge, and the slant height:
\[
l^2 = h^2 + \left(\frac{a}{2}\right)^2
\]
Substituting the values we have:
\[
(13.5)^2 = h^2 + (10)^2
\]
Calculating the squares:
\[
182.25 = h^2 + 100
\]
Now, subtract 100 from both sides:
\[
182.25 - 100 = h^2
\]
\[
82.25 = h^2
\]
Now, take the square root of both sides to find \( h \):
\[
h = \sqrt{82.25} \approx 9.1 \text{ meters}
\]
Thus, the height of the circus tent, rounded to the nearest tenth, is approximately **9.1 meters**.
Given:
- Base edge \( a = 20 \) meters
- Slant height \( l = 13.5 \) meters
First, we need to find half the base edge, which is:
\[
\frac{a}{2} = \frac{20}{2} = 10 \text{ meters}
\]
Now, we can use the Pythagorean theorem, which relates the height \( h \), half the base edge, and the slant height:
\[
l^2 = h^2 + \left(\frac{a}{2}\right)^2
\]
Substituting the values we have:
\[
(13.5)^2 = h^2 + (10)^2
\]
Calculating the squares:
\[
182.25 = h^2 + 100
\]
Now, subtract 100 from both sides:
\[
182.25 - 100 = h^2
\]
\[
82.25 = h^2
\]
Now, take the square root of both sides to find \( h \):
\[
h = \sqrt{82.25} \approx 9.1 \text{ meters}
\]
Thus, the height of the circus tent, rounded to the nearest tenth, is approximately **9.1 meters**.
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