Asked by JP

A 74 kg adult sits at one end of a 8.5 m long board. His 35 kg child sits on the other end.Where should the pivot be placed so that the board is balanced, ignoring the board's mass?
Answered by Julius- J
Just take the torque from where the adult sits. So it will be: 0 = (Force of the pivot)*(x) - (25)*(g)*(9). The force of the pivot can be calculated by taking the total force on the board. Which is (the force of the pivot) - (The adult's weight) - (The child's weight).
Answered by marmar
17.97
Answered by ihg6ul
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