Asked by JP
A 74 kg adult sits at one end of a 8.5 m long board. His 35 kg child sits on the other end.Where should the pivot be placed so that the board is balanced, ignoring the board's mass?
Answers
Answered by
Julius- J
Just take the torque from where the adult sits. So it will be: 0 = (Force of the pivot)*(x) - (25)*(g)*(9). The force of the pivot can be calculated by taking the total force on the board. Which is (the force of the pivot) - (The adult's weight) - (The child's weight).
Answered by
marmar
17.97
Answered by
ihg6ul
jfl
mbgk.n hhl.
mbgk.n hhl.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.