Question
What is the equation of this line?
Responses
y=12x−3
y equals fraction 1 half end fraction x minus 3
y=−12x−3
y equals negative fraction 1 half end fraction x minus 3
y=−2x−3
y equals negative 2 x minus 3
y=2x−3
y equals 2 x minus 3
Number graph ranging from negative 5 to 5 on both the x and y axis. A line passes through the point begin ordered pair 0 comma negative 3 end ordered pair and the point begin ordered pair 4 comma negative 1 end ordered pair
Responses
y=12x−3
y equals fraction 1 half end fraction x minus 3
y=−12x−3
y equals negative fraction 1 half end fraction x minus 3
y=−2x−3
y equals negative 2 x minus 3
y=2x−3
y equals 2 x minus 3
Number graph ranging from negative 5 to 5 on both the x and y axis. A line passes through the point begin ordered pair 0 comma negative 3 end ordered pair and the point begin ordered pair 4 comma negative 1 end ordered pair
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the equation of the line that passes through the points (0, -3) and (4, -1), we can first calculate the slope (m) of the line using the formula:
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
Plugging in the coordinates of the given points:
\[
m = \frac{-1 - (-3)}{4 - 0} = \frac{-1 + 3}{4} = \frac{2}{4} = \frac{1}{2}
\]
Now that we have the slope \( m = \frac{1}{2} \), we can use the point-slope form of the equation of a line, which is given by:
\[
y - y_1 = m(x - x_1)
\]
Using one of the points (0, -3):
\[
y - (-3) = \frac{1}{2}(x - 0)
\]
This simplifies to:
\[
y + 3 = \frac{1}{2}x
\]
Subtracting 3 from both sides:
\[
y = \frac{1}{2}x - 3
\]
Thus, the equation of the line is:
\[
y = \frac{1}{2}x - 3
\]
This corresponds to the response:
**y equals fraction 1 half end fraction x minus 3.**
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
Plugging in the coordinates of the given points:
\[
m = \frac{-1 - (-3)}{4 - 0} = \frac{-1 + 3}{4} = \frac{2}{4} = \frac{1}{2}
\]
Now that we have the slope \( m = \frac{1}{2} \), we can use the point-slope form of the equation of a line, which is given by:
\[
y - y_1 = m(x - x_1)
\]
Using one of the points (0, -3):
\[
y - (-3) = \frac{1}{2}(x - 0)
\]
This simplifies to:
\[
y + 3 = \frac{1}{2}x
\]
Subtracting 3 from both sides:
\[
y = \frac{1}{2}x - 3
\]
Thus, the equation of the line is:
\[
y = \frac{1}{2}x - 3
\]
This corresponds to the response:
**y equals fraction 1 half end fraction x minus 3.**
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