To determine when the rock hits the water using the equation \( h = -4.9t^2 + 10 \), we need to find the time \( t \) when the height \( h \) is equal to 0 (when the rock reaches the water level).
Setting the height \( h \) to 0, we have:
\[ 0 = -4.9t^2 + 10 \]
Rearranging gives:
\[ 4.9t^2 = 10 \]
Dividing by 4.9:
\[ t^2 = \frac{10}{4.9} \approx 2.04 \]
Taking the square root:
\[ t \approx \sqrt{2.04} \approx 1.43 \text{ seconds} \]
To create a table for this scenario, we might want to include time values around 1.43 seconds. A reasonable scale for the range could be in increments of 0.5 seconds or 1 second to ensure we capture the moment just before and when the rock hits the water.
Among the provided options, the best choice for a scale that can represent the time from 0 to a little over 1.43 seconds is 1 tenth (0.1 seconds). This allows for a detailed range of values leading up to the impact with the water.
So, the best answer is:
1 tenth