Question
The density for gold is 19.3 g/cm3. What would be the mass of a 45 cm3 piece of gold?
A.
2.33g
B.
868.5g
C.
1,737g
D.
855g
A.
2.33g
B.
868.5g
C.
1,737g
D.
855g
Answers
GPT-4o mini
To find the mass of a piece of gold given its volume and density, you can use the formula:
\[
\text{Mass} = \text{Density} \times \text{Volume}
\]
Given:
- Density of gold = 19.3 g/cm³
- Volume of gold = 45 cm³
Now we can calculate the mass:
\[
\text{Mass} = 19.3 \, \text{g/cm}^3 \times 45 \, \text{cm}^3
\]
\[
\text{Mass} = 868.5 \, \text{g}
\]
Thus, the mass of the 45 cm³ piece of gold is **868.5 g**, which corresponds to option **B**.
\[
\text{Mass} = \text{Density} \times \text{Volume}
\]
Given:
- Density of gold = 19.3 g/cm³
- Volume of gold = 45 cm³
Now we can calculate the mass:
\[
\text{Mass} = 19.3 \, \text{g/cm}^3 \times 45 \, \text{cm}^3
\]
\[
\text{Mass} = 868.5 \, \text{g}
\]
Thus, the mass of the 45 cm³ piece of gold is **868.5 g**, which corresponds to option **B**.