Question

Use the table to answer the question.

(x+3)(x+4)=0

x−3=0
x+4=0

x=3
x=−4

While using the Zero Product Property to find the values of x that make the quadratic equation (x+3)(x+4)
equals 0, Oliver completed the work provided in the table. Is Oliver’s work accurate?(1 point)
Responses

No, he should have a third column where he should set x=0
.
No, he should have a third column where he should set x equals 0 .

Yes, the work is accurate.
Yes, the work is accurate.

No, x−3=0
in the second row should be x+3=0
.
No, x minus 3 equals 0 in the second row should be x plus 3 equals 0 .

No, x+4=0
in the second row should be x−4=0
.

Answer 1

Oliver's work is not accurate. The equation (x+3)(x+4)=0 correctly factors the quadratic, and according to the Zero Product Property, each factor should be set equal to zero.

In the table, the factor (x+3) is incorrectly replaced with (x−3) in the second row. The correct equation should be:

- From (x+3)(x+4)=0, the factors are:
- x + 3 = 0 ➔ x = -3
- x + 4 = 0 ➔ x = -4

So the correct values of x that satisfy the equation are x = -3 and x = -4, not x = 3 and x = -4 as listed.

Therefore, the correct response is:

**No, x−3=0 in the second row should be x+3=0.**