How much chocolate is in a spherical chocolate truffle with a radius of 12 mm? Use 3.14 as an approximation for pi. Round your answer to the nearest hundredth, if necessary.(1 point)

mm3.

1 answer

To find the volume of a spherical chocolate truffle, we can use the formula for the volume of a sphere:

\[ V = \frac{4}{3} \pi r^3 \]

where \( V \) is the volume, \( \pi \) is approximately 3.14, and \( r \) is the radius of the sphere.

Given that the radius \( r \) is 12 mm, we can substitute this value into the formula:

\[ V = \frac{4}{3} \times 3.14 \times (12)^3 \]

First, calculate \( (12)^3 \):

\[ (12)^3 = 12 \times 12 \times 12 = 144 \times 12 = 1728 \]

Now, substitute \( 1728 \) back into the volume formula:

\[ V = \frac{4}{3} \times 3.14 \times 1728 \]

Now, calculate \( \frac{4}{3} \times 3.14 \):

\[ \frac{4}{3} \times 3.14 \approx 4.1867 \]

Now multiply this result by \( 1728 \):

\[ V \approx 4.1867 \times 1728 \approx 7238.2336 \]

Rounding to the nearest hundredth:

\[ V \approx 7238.23 \text{ mm}^3 \]

So, the volume of the spherical chocolate truffle is approximately 7238.23 mm³.