Question
Express the product left parenthesis, square root of, 10, end square root, minus, 3, right parenthesis, left parenthesis, square root of, 10, end square root, minus, 3, right parenthesis(
10
−3)(
10
−3) in simplest form.
10
−3)(
10
−3) in simplest form.
Answers
Answered by
GPT-4o mini
To express the product \( (\sqrt{10} - 3)(\sqrt{10} - 3) \) in simplest form, we can recognize that this is the square of a binomial. Specifically, it can be rewritten as:
\[
(\sqrt{10} - 3)^2
\]
We can expand this using the formula for the square of a binomial, \( (a - b)^2 = a^2 - 2ab + b^2 \), where \( a = \sqrt{10} \) and \( b = 3 \):
\[
(\sqrt{10})^2 - 2(\sqrt{10})(3) + 3^2
\]
Calculating each term:
1. \( (\sqrt{10})^2 = 10 \)
2. \( 2(\sqrt{10})(3) = 6\sqrt{10} \)
3. \( 3^2 = 9 \)
Putting it all together, we have:
\[
10 - 6\sqrt{10} + 9
\]
Now, simplify:
\[
10 + 9 - 6\sqrt{10} = 19 - 6\sqrt{10}
\]
Thus, the product \( (\sqrt{10} - 3)(\sqrt{10} - 3) \) in its simplest form is:
\[
\boxed{19 - 6\sqrt{10}}
\]
\[
(\sqrt{10} - 3)^2
\]
We can expand this using the formula for the square of a binomial, \( (a - b)^2 = a^2 - 2ab + b^2 \), where \( a = \sqrt{10} \) and \( b = 3 \):
\[
(\sqrt{10})^2 - 2(\sqrt{10})(3) + 3^2
\]
Calculating each term:
1. \( (\sqrt{10})^2 = 10 \)
2. \( 2(\sqrt{10})(3) = 6\sqrt{10} \)
3. \( 3^2 = 9 \)
Putting it all together, we have:
\[
10 - 6\sqrt{10} + 9
\]
Now, simplify:
\[
10 + 9 - 6\sqrt{10} = 19 - 6\sqrt{10}
\]
Thus, the product \( (\sqrt{10} - 3)(\sqrt{10} - 3) \) in its simplest form is:
\[
\boxed{19 - 6\sqrt{10}}
\]
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