Is the equation  3−5⋅(81√4)33−4=3−6  true or false? Select the response that correctly answers the question and provides the appropriate justification.(1 point)ResponsesTrue. The numerator simplifies to 3−2and 3−23−4≠3−6.True. The numerator simplifies to 3 to the negative 2 power   and the fraction with numerator 3 to the negative 2 power and denominator 3 to the negative 4 power is not equal to 3 to the negative 6 power.False. The numerator simplifies to 3−2 and 3−23−4≠3−6.False. The numerator simplifies to 3 to the negative 2 power and the fraction with numerator 3 to the negative 2 power and denominator 3 to the negative 4 power is not equal to 3 to the negative 6 power.True. (81−−√4)3=32 and 3−103−4=3−6True. open paren 4th root of 81 close paren cubed is equal to 3 squared and the fraction with numerator 3 to the negative 10 power and denominator 3 to the negative 4 power is equal to 3 to the negative 6 powerFalse. (81−−√4)3cannot be determined.

1 answer

To determine whether the equation \( 3^{-5 \cdot (\sqrt[4]{81})^3} \cdot 3^{-4} = 3^{-6} \) is true or false, let’s simplify the left-hand side.

Firstly, calculate \( \sqrt[4]{81} \): \[ \sqrt[4]{81} = \sqrt[4]{3^4} = 3 \]

Now we substitute this back into our equation: \[ 3^{-5 \cdot (3)^3} \cdot 3^{-4} \]

Next, calculate \( (3)^3 \): \[ (3)^3 = 27 \]

Thus, our expression simplifies to: \[ 3^{-5 \cdot 27} \cdot 3^{-4} = 3^{-135} \cdot 3^{-4} \]

Using the properties of exponents to combine the exponents: \[ 3^{-135 - 4} = 3^{-139} \]

Now we need to compare \( 3^{-139} \) with \( 3^{-6} \). Clearly, \[ 3^{-139} \neq 3^{-6} \]

Thus, the equation \( 3^{-5 \cdot (\sqrt[4]{81})^3} \cdot 3^{-4} = 3^{-6} \) is false.

The correct justification is: False. The numerator simplifies to \(3^{-139}\) and \(3^{-139} \neq 3^{-6}\).