To determine whether the equation \( 3^{-5 \cdot (\sqrt[4]{81})^3} \cdot 3^{-4} = 3^{-6} \) is true or false, let’s simplify the left-hand side.
Firstly, calculate \( \sqrt[4]{81} \): \[ \sqrt[4]{81} = \sqrt[4]{3^4} = 3 \]
Now we substitute this back into our equation: \[ 3^{-5 \cdot (3)^3} \cdot 3^{-4} \]
Next, calculate \( (3)^3 \): \[ (3)^3 = 27 \]
Thus, our expression simplifies to: \[ 3^{-5 \cdot 27} \cdot 3^{-4} = 3^{-135} \cdot 3^{-4} \]
Using the properties of exponents to combine the exponents: \[ 3^{-135 - 4} = 3^{-139} \]
Now we need to compare \( 3^{-139} \) with \( 3^{-6} \). Clearly, \[ 3^{-139} \neq 3^{-6} \]
Thus, the equation \( 3^{-5 \cdot (\sqrt[4]{81})^3} \cdot 3^{-4} = 3^{-6} \) is false.
The correct justification is: False. The numerator simplifies to \(3^{-139}\) and \(3^{-139} \neq 3^{-6}\).