Question

Three adult and three child movie tickets were purchased 75 the cost of each child ticket is 3 less the cost

Answer 1

Let's denote the cost of an adult ticket as \( A \) and the cost of a child ticket as \( C \). According to the information you've provided, we have the following equations:

1. The total cost for three adult tickets and three child tickets is \( 75 \):

\[
3A + 3C = 75
\]

2. The cost of each child ticket is $3 less than the cost of each adult ticket:

\[
C = A - 3
\]

Now, we can substitute the second equation into the first equation.

Substituting \( C \) in the first equation:

\[
3A + 3(A - 3) = 75
\]

Expanding the equation:

\[
3A + 3A - 9 = 75
\]
\[
6A - 9 = 75
\]

Now, add 9 to both sides:

\[
6A = 84
\]

Now, divide both sides by 6:

\[
A = 14
\]

Now that we have the cost of an adult ticket, we can find the cost of a child ticket using the second equation:

\[
C = A - 3 = 14 - 3 = 11
\]

So, the costs of the tickets are:
- Adult ticket: \( \$14 \)
- Child ticket: \( \$11 \)