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Convert the following equations form standard form to slope intercept form

6x+2y=10

1 answer

To convert the equation from standard form \(6x + 2y = 10\) to slope-intercept form \(y = mx + b\), we need to isolate \(y\).

Starting with the equation:

\[ 6x + 2y = 10 \]

  1. Subtract \(6x\) from both sides:

\[ 2y = -6x + 10 \]

  1. Now, divide every term by \(2\) to solve for \(y\):

\[ y = -3x + 5 \]

So, the equation in slope-intercept form is:

\[ y = -3x + 5 \]

Here, the slope \(m\) is \(-3\) and the y-intercept \(b\) is \(5\).