Asked by kymari davis-shanks
Volume of Cones, Cylinders, and Spheres Practice
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Question
Suppose a sphere and a cone share the same radius and the height of the cone is twice the radius. Which ratio describes the relationship between the formulas for the volume of a cone to the volume of a sphere?(1 point)
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Complete this assessment to review what you've learned. It will not count toward your grade.
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Question
Suppose a sphere and a cone share the same radius and the height of the cone is twice the radius. Which ratio describes the relationship between the formulas for the volume of a cone to the volume of a sphere?(1 point)
:
Remaining Attempts : 3
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Answers
Answered by
GPT-4o mini
To find the ratio of the volumes of the cone and the sphere given that they share the same radius (r) and the height of the cone is twice the radius (h = 2r), we can use the formulas for the volumes of a cone and a sphere.
The volume \( V \) of a cone is given by the formula:
\[
V_{cone} = \frac{1}{3} \pi r^2 h
\]
Since \( h = 2r \), we can substitute that into the formula:
\[
V_{cone} = \frac{1}{3} \pi r^2 (2r) = \frac{2}{3} \pi r^3
\]
The volume \( V \) of a sphere is given by the formula:
\[
V_{sphere} = \frac{4}{3} \pi r^3
\]
Now, we can form the ratio of the volume of the cone to the volume of the sphere:
\[
\text{Ratio} = \frac{V_{cone}}{V_{sphere}} = \frac{\frac{2}{3} \pi r^3}{\frac{4}{3} \pi r^3}
\]
The \( \frac{4}{3} \pi r^3 \) in the denominator will cancel out with the \( \frac{4}{3} \pi r^3 \) in the numerator, leading to:
\[
\text{Ratio} = \frac{2}{4} = \frac{1}{2}
\]
Thus, the ratio of the volumes of the cone to the sphere is:
\[
\frac{1}{2}
\]
The volume \( V \) of a cone is given by the formula:
\[
V_{cone} = \frac{1}{3} \pi r^2 h
\]
Since \( h = 2r \), we can substitute that into the formula:
\[
V_{cone} = \frac{1}{3} \pi r^2 (2r) = \frac{2}{3} \pi r^3
\]
The volume \( V \) of a sphere is given by the formula:
\[
V_{sphere} = \frac{4}{3} \pi r^3
\]
Now, we can form the ratio of the volume of the cone to the volume of the sphere:
\[
\text{Ratio} = \frac{V_{cone}}{V_{sphere}} = \frac{\frac{2}{3} \pi r^3}{\frac{4}{3} \pi r^3}
\]
The \( \frac{4}{3} \pi r^3 \) in the denominator will cancel out with the \( \frac{4}{3} \pi r^3 \) in the numerator, leading to:
\[
\text{Ratio} = \frac{2}{4} = \frac{1}{2}
\]
Thus, the ratio of the volumes of the cone to the sphere is:
\[
\frac{1}{2}
\]