Let's simplify the expression \(2\sqrt{8} + \sqrt{28} + 2\sqrt{8}\).
First, combine the \(2\sqrt{8}\) terms:
\[ 2\sqrt{8} + 2\sqrt{8} = 4\sqrt{8} \]
Next, we can simplify \(\sqrt{8}\) and \(\sqrt{28}\):
- \(\sqrt{8} = \sqrt{4 \cdot 2} = 2\sqrt{2}\)
- \(\sqrt{28} = \sqrt{4 \cdot 7} = 2\sqrt{7}\)
Now, substitute these back into the expression:
\[ 4\sqrt{8} + \sqrt{28} = 4(2\sqrt{2}) + 2\sqrt{7} \] \[ = 8\sqrt{2} + 2\sqrt{7} \]
This is the simplified form of the expression. Therefore, the answer is:
\[ 8\sqrt{2} + 2\sqrt{7} \]