moles HCl initially = M x L.
moles NaOH = M x L
moles NaOH = moles HCl in excess.
moles HCl initial - mols HCl excess = moles used by actacid.
I'm confused by "express the volum of HCl solution in liters" but the information is above. If the answer is to be expressed in liters, then I would suggest molarity = moles/L and rearrange to
L - moles/M = moles used/M
A student performs a back-titration to determine the cost -effectiveness of an antacid. A tablet with a retail cost of $0.053 is dissolved in 25.00 ml of 1.000 M HCl, then back-titrated with 1.000 M NaOH. Exactly 14.82 ml of NaOH solution is required to reach the endpoint. Express the volume of HCl solution in liters.
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