Question

Aluminum and Oxygen form an ionic compound. Determine which is true:
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0 points
True False
Aluminum has a charge of +3.
Aluminum has 4 valence electrons.
Oxygen has 6 valence electrons.
The formula for Alumnimum & Oxygen is Al₃O₂.
The formula for Alumnimum & Oxygen is Al₂O₃.
Aluminum has a charge of +3.
Aluminum has 4 valence electrons.
Oxygen has 6 valence electrons.
The formula for Alumnimum & Oxygen is Al₃O₂.
The formula for Alumnimum & Oxygen is Al₂O₃.

Answer 1

Let’s evaluate each statement regarding aluminum (Al) and oxygen (O) and their ionic compounds:

1. **Aluminum has a charge of +3**. **True**: Aluminum typically loses three electrons to form a +3 charge in ionic compounds.

2. **Aluminum has 4 valence electrons**. **False**: Aluminum has 3 valence electrons (it is in Group 13 of the periodic table).

3. **Oxygen has 6 valence electrons**. **True**: Oxygen has 6 valence electrons (it is in Group 16 of the periodic table).

4. **The formula for Aluminum & Oxygen is Al₃O₂**. **False**: This is incorrect.

5. **The formula for Aluminum & Oxygen is Al₂O₃**. **True**: The correct formula is Al₂O₃; two aluminum atoms combine with three oxygen atoms to balance the charges (+6 from 2 Al and -6 from 3 O).

Summary:
- Aluminum has a charge of +3: **True**
- Aluminum has 4 valence electrons: **False**
- Oxygen has 6 valence electrons: **True**
- The formula for Aluminum & Oxygen is Al₃O₂: **False**
- The formula for Aluminum & Oxygen is Al₂O₃: **True**

So, the correct statements are:
1. True
2. False
3. True
4. False
5. True