Question
create a solve for x medium colecity pecuation
Answers
Answered by
GPT-4o mini
It looks like there might be a slight misunderstanding in your request. "Colecity pecuation" isn't a clear term, but it seems like you might be asking for a medium difficulty algebraic equation to solve for \( x \). Here’s an example along with the solution:
### Example Problem:
Solve for \( x \) in the equation:
\[ 3(2x - 4) + 5 = 2(x + 8) \]
### Solution:
1. **Distribute on both sides:**
\[
3(2x) - 3(4) + 5 = 2(x) + 2(8)
\]
Which simplifies to:
\[
6x - 12 + 5 = 2x + 16
\]
So we have:
\[
6x - 7 = 2x + 16
\]
2. **Move all terms involving \( x \) to one side and constant terms to the other:**
\[
6x - 2x = 16 + 7
\]
Simplifying this gives:
\[
4x = 23
\]
3. **Divide both sides by 4:**
\[
x = \frac{23}{4} \quad \text{or} \quad x = 5.75
\]
### Final Answer:
\[
x = \frac{23}{4} \quad \text{or} \quad 5.75
\]
If this isn't what you were looking for, please provide more specific details, and I'll be happy to assist!
### Example Problem:
Solve for \( x \) in the equation:
\[ 3(2x - 4) + 5 = 2(x + 8) \]
### Solution:
1. **Distribute on both sides:**
\[
3(2x) - 3(4) + 5 = 2(x) + 2(8)
\]
Which simplifies to:
\[
6x - 12 + 5 = 2x + 16
\]
So we have:
\[
6x - 7 = 2x + 16
\]
2. **Move all terms involving \( x \) to one side and constant terms to the other:**
\[
6x - 2x = 16 + 7
\]
Simplifying this gives:
\[
4x = 23
\]
3. **Divide both sides by 4:**
\[
x = \frac{23}{4} \quad \text{or} \quad x = 5.75
\]
### Final Answer:
\[
x = \frac{23}{4} \quad \text{or} \quad 5.75
\]
If this isn't what you were looking for, please provide more specific details, and I'll be happy to assist!
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