Question

A can ha sa diameter of 6 inches and a height of 4 inches How amny square inches of paper will be needed for the label on the OUTSIDE of the can? Use 3.14 for pi
75.36
131.88
150.72
376.8
are you sure?

Answer 1

To calculate the area of the paper needed for the label on the outside of the cylindrical can, we need to find the lateral surface area of the cylinder. The formula for the lateral surface area \( A \) of a cylinder is given by:

\[
A = 2 \pi r h
\]

where:
- \( r \) is the radius of the base of the cylinder,
- \( h \) is the height of the cylinder.

### Given:
- Diameter = 6 inches
Thus, the radius \( r = \frac{6}{2} = 3 \) inches.
- Height \( h = 4 \) inches.

### Substituting the values into the formula:

\[
A = 2 \pi (3) (4)
\]

Using \( \pi \approx 3.14 \):

\[
A = 2 \times 3.14 \times 3 \times 4
\]
\[
A = 2 \times 3.14 \times 12
\]
\[
A = 2 \times 37.68
\]
\[
A = 75.36 \text{ square inches}
\]

So, the area of the paper needed for the label on the outside of the can is \( 75.36 \) square inches.

**Answer: 75.36 square inches**.

Answer 2

you sure

Answer 3

Yes, I am sure. The calculation for the lateral surface area of a cylinder is correct. Let's go through it again step-by-step:

1. **Calculate the radius from the diameter:**
- Diameter = 6 inches
- Radius \( r = \frac{6}{2} = 3 \) inches

2. **Use the height of the cylinder:**
- Height \( h = 4 \) inches

3. **Formula for lateral surface area of a cylinder:**
\[
A = 2 \pi r h
\]

4. **Substituting the values into the formula:**
\[
A = 2 \pi (3) (4)
\]

5. **Now substitute \( \pi \approx 3.14 \):**
\[
A = 2 \times 3.14 \times 3 \times 4
\]
- First calculate \( 3 \times 4 = 12 \)
- Then calculate \( 2 \times 3.14 \times 12 \):
\[
2 \times 3.14 = 6.28
\]
\[
6.28 \times 12 = 75.36
\]

Therefore, the area of paper needed for the label on the outside of the can is indeed **75.36 square inches**. This is the correct answer.