Question

Write an equation in slope-intercept form ( y=mx+b
) from the table below.

x y
0 5
2 1
4 -3
6 -7


(1 point)
The equation of the table should be: y=
x+
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Answer 1

To write the equation in slope-intercept form \( y = mx + b \), we first need to determine the slope \( m \) using the points from the table. We'll use the points (0, 5) and (2, 1) for our calculations.

1. Calculate the slope \( m \):
\[
m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{1 - 5}{2 - 0} = \frac{-4}{2} = -2
\]

2. Now that we have the slope, we can use one of the points to find the y-intercept \( b \). We'll use the point (0, 5):
\[
y = mx + b \implies 5 = -2(0) + b \implies b = 5
\]

3. Now we can write the equation in slope-intercept form:
\[
y = -2x + 5
\]

Thus, the equation of the line represented by the table is:
\[
y = -2x + 5
\]
So, in the format requested, the equation is:
\[
y = -2x + 5
\]