Question

what is a point on a graph described by this function y = (2x + 1)^2 - 4

Answer 1

To find a point on the graph of the function \( y = (2x + 1)^2 - 4 \), you can choose a value for \( x \) and then calculate the corresponding value of \( y \).

Let's choose \( x = 0 \):

1. Substitute \( x = 0 \) into the function:
\[
y = (2(0) + 1)^2 - 4
\]
\[
y = (0 + 1)^2 - 4
\]
\[
y = 1^2 - 4
\]
\[
y = 1 - 4
\]
\[
y = -3
\]

So, the point \( (0, -3) \) lies on the graph of the function \( y = (2x + 1)^2 - 4 \). You can choose other values for \( x \) to find additional points as well.