what is a point on a graph described by this function y = (2x + 1)^2 - 4

1 answer

To find a point on the graph of the function \( y = (2x + 1)^2 - 4 \), you can choose a value for \( x \) and then calculate the corresponding value of \( y \).

Let's choose \( x = 0 \):

  1. Substitute \( x = 0 \) into the function: \[ y = (2(0) + 1)^2 - 4 \] \[ y = (0 + 1)^2 - 4 \] \[ y = 1^2 - 4 \] \[ y = 1 - 4 \] \[ y = -3 \]

So, the point \( (0, -3) \) lies on the graph of the function \( y = (2x + 1)^2 - 4 \). You can choose other values for \( x \) to find additional points as well.