Question

Subtract: (3b−2c)−(6c+2b)−(b+c)
.(1 point)

Answer 1

To subtract the expression \((3b - 2c) - (6c + 2b) - (b + c)\), we first distribute the negative signs and then combine like terms.

1. Rewrite the expression by distributing the negative signs:

\[
(3b - 2c) - (6c + 2b) - (b + c) = 3b - 2c - 6c - 2b - b - c
\]

2. Now, combine like terms:

- Combine the \(b\) terms:
\[
3b - 2b - b = (3 - 2 - 1)b = 0b = 0
\]

- Combine the \(c\) terms:
\[
-2c - 6c - c = (-2 - 6 - 1)c = -9c
\]

Putting it all together, we have:

\[
0 - 9c = -9c
\]

Thus, the result of the subtraction is:

\[
\boxed{-9c}
\]