Subtract: (3b−2c)−(6c+2b)−(b+c)

Question

.(1 point)

Answer 1

To subtract the expression \((3b - 2c) - (6c + 2b) - (b + c)\), we first distribute the negative signs and then combine like terms.

1. Rewrite the expression by distributing the negative signs:

\[ (3b - 2c) - (6c + 2b) - (b + c) = 3b - 2c - 6c - 2b - b - c \]

2. Now, combine like terms:

• Combine the \(b\) terms: \[ 3b - 2b - b = (3 - 2 - 1)b = 0b = 0 \]

• Combine the \(c\) terms: \[ -2c - 6c - c = (-2 - 6 - 1)c = -9c \]

Putting it all together, we have:

\[ 0 - 9c = -9c \]

Thus, the result of the subtraction is:

\[ \boxed{-9c} \]