Identify the transformations for the function f(x)=3cos(-x+π/3)-2.

1 answer

To identify the transformations for the function \( f(x) = 3 \cos(-x + \frac{\pi}{3}) - 2 \), we can break it down into components based on the standard cosine function \( \cos(x) \).

  1. Start with the base function: The base function is \( \cos(x) \).

  2. Horizontal reflection: The term \( -x \) indicates a reflection across the vertical axis. So, \( \cos(-x) = \cos(x) \) reflects the function horizontally.

  3. Horizontal shift: The term \( +\frac{\pi}{3} \) in \( -x + \frac{\pi}{3} \) indicates a horizontal shift. Since it's part of the argument of the cosine function, this means the function is shifted to the left by \( \frac{\pi}{3} \).

  4. Vertical stretch: The coefficient \( 3 \) in front of the cosine function indicates a vertical stretch of the graph. The amplitude of the cosine function is stretched from \( 1 \) to \( 3 \).

  5. Vertical shift: The term \( -2 \) at the end indicates a vertical shift downward by \( 2 \) units.

Combining all these transformations, we can summarize them as:

  • Reflect across the vertical axis (due to the negative sign in front of \( x \)).
  • Shift left by \( \frac{\pi}{3} \) units.
  • Stretch vertically by a factor of \( 3 \).
  • Shift down by \( 2 \) units.

In conclusion, the transformations of the function \( f(x) = 3 \cos(-x + \frac{\pi}{3}) - 2 \) are:

  1. Reflect in the vertical axis.
  2. Shift left by \( \frac{\pi}{3} \).
  3. Stretch vertically by a factor of \( 3 \).
  4. Shift down by \( 2 \) units.