To determine the weight of the water displaced by the test object, you typically would need to know the volume of the object submerged in water and the density of water to calculate the weight.
However, since the hint refers to earlier questions (4.1 and 4.2), it's likely that those questions provided specific values for either the volume of the object or the weight of the water displaced.
The weight of the water displaced can be derived from the formula:
\[ \text{Weight of water displaced} = \text{Volume of water displaced} \times \text{Density of water} \times g \]
where:
- The density of water is approximately \( 1000 , \text{kg/m}^3 \),
- \( g \) (the acceleration due to gravity) is approximately \( 9.8 , \text{m/s}^2 \).
If you have further details from questions 4.1 and 4.2 regarding the volume of the test object, you can calculate the weight of the water displaced accordingly.
Without that context, it's challenging to select the correct answer definitively. However, the potential options provided (5 points):
- 4.9 N
- 9.8 N
- 49 N
- 98 N
Typically correspond to weights that could arise from different volumes of water displaced, given the standard density of water.
If we assume that the weight corresponds to the volume of 5 kg of water displaced (since \( 5 , \text{kg} \times 9.8 , \text{m/s}^2 = 49 , \text{N} \)), the likely correct answer would be:
49 N
This assumes that the volume displaced corresponds to the weight of 5 kg of water. If either 4.1 or 4.2 gave another specific volume or weight for clarification, the answer might differ.