To find the range of the function \( f(x) = 4x - 2 \) given the domain \( {-2, -1, 0, 1, 2} \), we will evaluate \( f(x) \) at each of the values in the domain.
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For \( x = -2 \): \[ f(-2) = 4(-2) - 2 = -8 - 2 = -10 \]
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For \( x = -1 \): \[ f(-1) = 4(-1) - 2 = -4 - 2 = -6 \]
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For \( x = 0 \): \[ f(0) = 4(0) - 2 = 0 - 2 = -2 \]
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For \( x = 1 \): \[ f(1) = 4(1) - 2 = 4 - 2 = 2 \]
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For \( x = 2 \): \[ f(2) = 4(2) - 2 = 8 - 2 = 6 \]
Now, we can compile the outputs:
- From \( x = -2 \) we get \( -10 \)
- From \( x = -1 \) we get \( -6 \)
- From \( x = 0 \) we get \( -2 \)
- From \( x = 1 \) we get \( 2 \)
- From \( x = 2 \) we get \( 6 \)
Putting these values together, the resulting outputs are: \(-10, -6, -2, 2, 6\).
Thus, the range of the function over the specified domain is:
\[ {-10, -6, -2, 2, 6} \]
From the options given, the correct one is:
{-10, -6, -2, 2, 6}