Question
what is the length of the hypotenuse if necessary round to the nearest tenth 2 in and 2 in
Answers
GPT-4o mini
To find the length of the hypotenuse in a right triangle with both legs measuring 2 inches, you can use the Pythagorean theorem:
\[
c = \sqrt{a^2 + b^2}
\]
In this case, both \( a \) and \( b \) are 2 inches:
\[
c = \sqrt{2^2 + 2^2} = \sqrt{4 + 4} = \sqrt{8}
\]
Calculating \( \sqrt{8} \):
\[
\sqrt{8} = \sqrt{4 \times 2} = \sqrt{4} \cdot \sqrt{2} = 2\sqrt{2} \approx 2 \times 1.414 \approx 2.828
\]
Rounding to the nearest tenth:
\[
c \approx 2.8 \, \text{in}
\]
Therefore, the length of the hypotenuse is approximately **2.8 inches**.
\[
c = \sqrt{a^2 + b^2}
\]
In this case, both \( a \) and \( b \) are 2 inches:
\[
c = \sqrt{2^2 + 2^2} = \sqrt{4 + 4} = \sqrt{8}
\]
Calculating \( \sqrt{8} \):
\[
\sqrt{8} = \sqrt{4 \times 2} = \sqrt{4} \cdot \sqrt{2} = 2\sqrt{2} \approx 2 \times 1.414 \approx 2.828
\]
Rounding to the nearest tenth:
\[
c \approx 2.8 \, \text{in}
\]
Therefore, the length of the hypotenuse is approximately **2.8 inches**.