Find the value of the function y=3x2−21 when x=4. y=?


.

1 answer

To find the value of the function \( y = 3x^2 - 21 \) when \( x = 4 \), we substitute \( 4 \) for \( x \):

\[ y = 3(4)^2 - 21 \]

Calculating \( (4)^2 \):

\[ (4)^2 = 16 \]

Now substitute back into the equation:

\[ y = 3(16) - 21 \]

Calculating \( 3(16) \):

\[ 3(16) = 48 \]

Now substituting that back:

\[ y = 48 - 21 \]

Calculating \( 48 - 21 \):

\[ y = 27 \]

Thus, the value of the function when \( x = 4 \) is

\[ \boxed{27} \]