Solve ln 5 + ln 2x = 3.

(1 point)
Responses

x equals start fraction e superscript 3 baseline minus 5 over 2 end fraction
Image with alt text: x equals start fraction e superscript 3 baseline minus 5 over 2 end fraction

x equals start fraction e superscript 3 baseline over 10 end fraction
Image with alt text: x equals start fraction e superscript 3 baseline over 10 end fraction

x equals start fraction 3 over ln 10 end fraction
Image with alt text: x equals start fraction 3 over ln 10 end fraction

x equals start fraction 3 minus ln 5 over 2 end fraction

1 answer

To solve the equation \( \ln 5 + \ln 2x = 3 \), we can use the properties of logarithms.

First, we can combine the logarithms on the left side:

\[ \ln(5 \cdot 2x) = 3 \]

This simplifies to:

\[ \ln(10x) = 3 \]

Next, we exponentiate both sides to eliminate the natural logarithm:

\[ 10x = e^3 \]

Now, we can solve for \( x \):

\[ x = \frac{e^3}{10} \]

Thus, the solution is:

\[ x = \frac{e^3}{10} \]

This corresponds to the response:

x equals start fraction e superscript 3 baseline over 10 end fraction.