Question

Select two values for `x` that would make `8+2x\le20` true.

Answer 1

To solve the inequality \( 8 + 2x \le 20 \), we first isolate \( x \).

1. Subtract 8 from both sides:
\[
2x \le 20 - 8
\]
\[
2x \le 12
\]

2. Divide both sides by 2:
\[
x \le 6
\]

Now we have \( x \le 6 \). Any value less than or equal to 6 will satisfy the inequality. Here are two examples of such values:

1. \( x = 5 \)
2. \( x = 6 \)

Both of these values make \( 8 + 2x \le 20 \) true:
- For \( x = 5 \):
\[
8 + 2(5) = 8 + 10 = 18 \quad (\text{which is } \le 20)
\]

- For \( x = 6 \):
\[
8 + 2(6) = 8 + 12 = 20 \quad (\text{which is } \le 20)
\]

To summarize, two values for \( x \) that satisfy the inequality are \( 5 \) and \( 6 \).