Asked by tete
0.1276 of a monoprotic acid (molar mass 110g/mol) was dissolved in 25ml of water.The pH of the solution was found to be 5.87 after the addition of 10.0ml of 0.0633 M NaOH.The Ka of acid is.......................
Answers
Answered by
DrBob222
HA + NaOH ==> NaA + H2O
Calculate moles HA from the data given. Calculate moles NaOH, determine moles NaA formed and moles HA remaining, plug into Henderson-Hasselbalch equation and solve for pKa, then Ka. Post your work if you get stuck.
Calculate moles HA from the data given. Calculate moles NaOH, determine moles NaA formed and moles HA remaining, plug into Henderson-Hasselbalch equation and solve for pKa, then Ka. Post your work if you get stuck.
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