Question
Solve.
The population of a particular country was 29 million in 1980; in 1989, it was 36 million. The exponential growth function A=29e^kt describes the population of this country t years after 1980. Use the fact that 9 years after 1980 the population increased by 7 million to find k to three decimal places.
The population of a particular country was 29 million in 1980; in 1989, it was 36 million. The exponential growth function A=29e^kt describes the population of this country t years after 1980. Use the fact that 9 years after 1980 the population increased by 7 million to find k to three decimal places.
Answers
36 = 29 e^(9k)
1.24138 = e^(9k)
9k = ln (1.24138)
k = ln (1.24138)/9
= ....
1.24138 = e^(9k)
9k = ln (1.24138)
k = ln (1.24138)/9
= ....
36M=29M*e^k9
take the ln of each side.
ln(36)=ln29+ 9k
k= (ln(36/29)) /9
take the ln of each side.
ln(36)=ln29+ 9k
k= (ln(36/29)) /9
Thank you again! Both of u. much appreciated
Related Questions
The population of a region is growing exponentially. There were 40 million people in 1980 (when t=0)...
A table of the U.S. population in millions indicated in 1960 the population was 181 million, in 1970...
In 1980, the population of a certain country was about 161 000. since then the population has decrea...
Year 1940 1950 1960 1970 1980
Rate of change (million people per year) 29 49 67 76 98
If the pop...