Use the image to answer the question.

A number line is shown ranging from negative 10 to 10 with numbers listed in unit increments. A closed point is plotted on the number line at 5. A leftward arrow is marked on the number line that originates at the closed point and goes beyond negative 10.

Hessa solved an inequality and graphed the solution on the number line. Which of the following inequalities did she solve?

(1 point)
Responses

1/5x−3/5≤2/5
Start Fraction 1 over 5 end fraction x minus Start Fraction 3 over 5 end fraction less than or equal to Start Fraction 2 over 5 end fraction

3/5x+2/5≥3 2/5
Start Fraction 3 over 5 end fraction x plus Start Fraction 2 over 5 end fraction greater than or equal to 3 Start Fraction 2 over 5 end fraction

3/7x+1/7≤1 6/7
Start Fraction 3 over 7 end fraction x plus Start Fraction 1 over 7 end fraction less than or equal 1 Start Fraction 6 over 7 end fraction

2/5x−4/5≥1 1/5
Start Fraction 2 over 5 end fraction x minus Start Fraction 4 over 5 end fraction greater than or equal to 1 Start Fraction 1 over 5 end fraction

1 answer

To determine which inequality Hessa solved, we need to analyze the closed point at 5 and the leftward arrow indicating that the solution includes numbers less than or equal to 5.

  1. A closed point at 5 means that the solution includes 5 itself.
  2. The leftward arrow indicates that the values extend to negative infinity, meaning the solution should be of the form \( x \leq 5 \).

Now, let's check each of the given inequalities to see which one results in \( x \leq 5 \):

  1. \( \frac{1}{5}x - \frac{3}{5} \leq \frac{2}{5} \):

    • Multiply all terms by 5: \( x - 3 \leq 2 \)
    • Adding 3 to both sides: \( x \leq 5 \)
      This matches the graphical representation.
  2. \( \frac{3}{5}x + \frac{2}{5} \geq 3 \frac{2}{5} \):

    • Rewrite \( 3 \frac{2}{5} \) as \( \frac{17}{5} \).
    • Multiply all terms by 5: \( 3x + 2 \geq 17 \)
    • Subtracting 2 gives: \( 3x \geq 15 \)
    • Dividing by 3: \( x \geq 5 \)
      This does not match the graphical representation.
  3. \( \frac{3}{7}x + \frac{1}{7} \leq 1 \frac{6}{7} \):

    • Rewrite \( 1 \frac{6}{7} \) as \( \frac{13}{7} \).
    • Multiply all terms by 7: \( 3x + 1 \leq 13 \)
    • Subtracting 1 gives: \( 3x \leq 12 \)
    • Dividing by 3: \( x \leq 4 \)
      This does not match the graphical representation.
  4. \( \frac{2}{5}x - \frac{4}{5} \geq 1 \frac{1}{5} \):

    • Rewrite \( 1 \frac{1}{5} \) as \( \frac{6}{5} \).
    • Multiply all terms by 5: \( 2x - 4 \geq 6 \)
    • Adding 4 to both sides: \( 2x \geq 10 \)
    • Dividing by 2: \( x \geq 5 \)
      This does not match the graphical representation.

Based on the analysis, the inequality Hessa solved that matches the closed point at 5 and extends leftward is:

\( \frac{1}{5}x - \frac{3}{5} \leq \frac{2}{5} \).