Question
Which point plotted on the grid represents a solution to the system of inequalities graphed?
y>−2x+3
𝑦
>
−
2
𝑥
+
3
y<3x−3
𝑦
<
3
𝑥
−
3
(1 point)
The point (,) represents a solution to the system.
y>−2x+3
𝑦
>
−
2
𝑥
+
3
y<3x−3
𝑦
<
3
𝑥
−
3
(1 point)
The point (,) represents a solution to the system.
Answers
GPT-4o mini
To determine which point represents a solution to the system of inequalities given:
1. \( y > -2x + 3 \)
2. \( y < 3x - 3 \)
you'll need to find a point that satisfies both inequalities.
### Steps to Check for Solutions:
1. **Check the first inequality \( y > -2x + 3 \)**:
- Choose a point (x, y) and plug in the values to see if it makes the inequality true.
2. **Check the second inequality \( y < 3x - 3 \)**:
- Similarly, plug in the (x, y) values into this inequality.
### Example Points:
Let's say we check the point \( (0, 5) \):
1. For \( y > -2x + 3 \):
- Plug in \( x = 0 \) and \( y = 5 \):
- \( 5 > -2(0) + 3 \) -> \( 5 > 3 \) (True)
2. For \( y < 3x - 3 \):
- Plug in \( x = 0 \) and \( y = 5 \):
- \( 5 < 3(0) - 3 \) -> \( 5 < -3 \) (False)
So, \( (0, 5) \) is **not** a solution.
### Try another point \( (1, 1) \):
1. For \( y > -2x + 3 \):
- \( 1 > -2(1) + 3 \) -> \( 1 > 1 \) (False)
### Let's test \( (0, 4) \):
1. For \( y > -2x + 3 \):
- \( 4 > -2(0) + 3 \) -> \( 4 > 3 \) (True)
2. For \( y < 3x - 3 \):
- \( 4 < 3(0) - 3 \) -> \( 4 < -3 \) (False)
### In summary:
You would need to check various points until you find one that satisfies both inequalities.
If you have a specific point (x, y) in mind, check it against both inequalities and see if it meets both conditions. If you want help checking a specific point, please provide it!
1. \( y > -2x + 3 \)
2. \( y < 3x - 3 \)
you'll need to find a point that satisfies both inequalities.
### Steps to Check for Solutions:
1. **Check the first inequality \( y > -2x + 3 \)**:
- Choose a point (x, y) and plug in the values to see if it makes the inequality true.
2. **Check the second inequality \( y < 3x - 3 \)**:
- Similarly, plug in the (x, y) values into this inequality.
### Example Points:
Let's say we check the point \( (0, 5) \):
1. For \( y > -2x + 3 \):
- Plug in \( x = 0 \) and \( y = 5 \):
- \( 5 > -2(0) + 3 \) -> \( 5 > 3 \) (True)
2. For \( y < 3x - 3 \):
- Plug in \( x = 0 \) and \( y = 5 \):
- \( 5 < 3(0) - 3 \) -> \( 5 < -3 \) (False)
So, \( (0, 5) \) is **not** a solution.
### Try another point \( (1, 1) \):
1. For \( y > -2x + 3 \):
- \( 1 > -2(1) + 3 \) -> \( 1 > 1 \) (False)
### Let's test \( (0, 4) \):
1. For \( y > -2x + 3 \):
- \( 4 > -2(0) + 3 \) -> \( 4 > 3 \) (True)
2. For \( y < 3x - 3 \):
- \( 4 < 3(0) - 3 \) -> \( 4 < -3 \) (False)
### In summary:
You would need to check various points until you find one that satisfies both inequalities.
If you have a specific point (x, y) in mind, check it against both inequalities and see if it meets both conditions. If you want help checking a specific point, please provide it!