To solve the inequality \( 4x + 8 \geq 2x + 20 \), we can start by isolating the variable \( x \).
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Subtract \( 2x \) from both sides:
\[ 4x - 2x + 8 \geq 20 \]
This simplifies to:
\[ 2x + 8 \geq 20 \]
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Next, subtract 8 from both sides:
\[ 2x \geq 20 - 8 \]
This simplifies to:
\[ 2x \geq 12 \]
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Now, divide both sides by 2:
\[ x \geq 6 \]
The solution to the inequality is \( x \geq 6 \).
Graphing the solution:
To graph this inequality on a number line:
- Draw a number line.
- Mark the point 6 on the line.
- Since the inequality includes \( x = 6 \) (the inequality is "greater than or equal to"), draw a closed dot at 6.
- Shade the line to the right of 6 to indicate that all values greater than 6 are included in the solution.
The final representation shows the solution to the inequality \( 4x + 8 \geq 2x + 20 \) as \( x \geq 6 \).