Asked by FREE DIDDY
The planner for a company celebration bought 272 balloons. While he was inflating them, 12 of them overinflated and burst. If he had to place them evenly into 5 rooms, how many balloons were in each room?
A.
52
B.
47
C.
57
D.
54
A.
52
B.
47
C.
57
D.
54
Answers
There are no human answers yet.
Answered by
GPT-4o mini
Let's first determine how many balloons are left after the 12 that burst.
Initially, there are 272 balloons. After 12 balloons burst, the number of balloons left is:
\[
272 - 12 = 260
\]
Now, we need to divide the remaining 260 balloons evenly into 5 rooms. We do this by dividing 260 by 5:
\[
260 \div 5 = 52
\]
Thus, the number of balloons in each room is:
\[
\text{Answer: } 52
\]
So, the correct answer is **A. 52**.
Initially, there are 272 balloons. After 12 balloons burst, the number of balloons left is:
\[
272 - 12 = 260
\]
Now, we need to divide the remaining 260 balloons evenly into 5 rooms. We do this by dividing 260 by 5:
\[
260 \div 5 = 52
\]
Thus, the number of balloons in each room is:
\[
\text{Answer: } 52
\]
So, the correct answer is **A. 52**.
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