A graph shows four quadrants with the x-axis and y-axis both ranging from negative 10 to positive 10 in increments of 1. Unlabeled points are plotted at left parenthesis negative 6 comma 8 right parenthesis, left parenthesis 4 comma 8 right parenthesis, left parenthesis 4 comma negative 3 right parenthesis, and left parenthesis negative 6 comma negative 3 right parenthesis. A straight line joins the four points forming a rectangle.


What is the length of the diagonal of the rectangle? Round your answer to the nearest hundredth, if necessary.
(1 point)
units
Remaining Attempts : 3

1 answer

To find the length of the diagonal of the rectangle defined by the given points, we first need to determine the coordinates of the opposite corners of the rectangle. The points you provided are:

  1. \((-6, 8)\)
  2. \((4, 8)\)
  3. \((4, -3)\)
  4. \((-6, -3)\)

From these points, the rectangle can be visualized, and one diagonal can be formed using the points \((-6, 8)\) and \((4, -3)\).

To calculate the length of the diagonal, we can use the distance formula, which is given by:

\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \]

Substituting the coordinates of the points \((-6, 8)\) and \((4, -3)\):

  • \(x_1 = -6\)
  • \(y_1 = 8\)
  • \(x_2 = 4\)
  • \(y_2 = -3\)

Substituting these values into the formula:

\[ d = \sqrt{(4 - (-6))^2 + (-3 - 8)^2} \] \[ = \sqrt{(4 + 6)^2 + (-3 - 8)^2} \] \[ = \sqrt{(10)^2 + (-11)^2} \] \[ = \sqrt{100 + 121} \] \[ = \sqrt{221} \]

Now, we can calculate \(\sqrt{221}\):

\[ \sqrt{221} \approx 14.835 \]

Rounding to the nearest hundredth, the length of the diagonal is approximately:

\[ \boxed{14.84} \text{ units} \]