Using polar coordinates, evaluate the integral which gives the area which lies in the first quadrant between the circles x^2+y^2=64 and x^2 - 8x + y^2 = 0.
3 answers
14 pi
the answer u gave me is incorrect. and please tell me the method u tried
You don't need Calculus to do this.
The outer circle has centre at (0,0) and has radius 8
The other circle has centre (4,0) and radius 4, so the touch at (8,0)
The big circle has area 64π, so the area in the first quad is 16π
The smaller circle has area 16π and half of it lies in quad I, so the area in there is 8π
So the area between the big circle and the little circle in quad I = 16π-8π = 8π
The outer circle has centre at (0,0) and has radius 8
The other circle has centre (4,0) and radius 4, so the touch at (8,0)
The big circle has area 64π, so the area in the first quad is 16π
The smaller circle has area 16π and half of it lies in quad I, so the area in there is 8π
So the area between the big circle and the little circle in quad I = 16π-8π = 8π
1 answer