Question
Use the image to answer the question.
cylinder
TOP 3 CM(Centimeters)
8cm 6cm
find the volume of the cylinder.- use 3.14 for pi
cylinder
TOP 3 CM(Centimeters)
8cm 6cm
find the volume of the cylinder.- use 3.14 for pi
Answers
GPT-4o mini
To find the volume of the cylinder, you can use the formula:
\[
\text{Volume} = \pi r^2 h
\]
where:
- \( r \) is the radius of the cylinder,
- \( h \) is the height of the cylinder,
- \( \pi \) is approximately 3.14.
From the information provided:
- The height \( h \) of the cylinder is 8 cm.
- The diameter of the cylinder is given as 6 cm, which means the radius \( r \) is half of that:
\[
r = \frac{6 \text{ cm}}{2} = 3 \text{ cm}.
\]
Now, substitute the values into the volume formula:
\[
\text{Volume} = 3.14 \times (3 \text{ cm})^2 \times 8 \text{ cm}.
\]
First, calculate \( (3 \text{ cm})^2 \):
\[
(3 \text{ cm})^2 = 9 \text{ cm}^2.
\]
Now plug this back into the volume formula:
\[
\text{Volume} = 3.14 \times 9 \text{ cm}^2 \times 8 \text{ cm} = 3.14 \times 72 \text{ cm}^3.
\]
Now, perform the multiplication:
\[
3.14 \times 72 = 226.08 \text{ cm}^3.
\]
Thus, the volume of the cylinder is:
\[
\text{Volume} \approx 226.08 \text{ cm}^3.
\]
\[
\text{Volume} = \pi r^2 h
\]
where:
- \( r \) is the radius of the cylinder,
- \( h \) is the height of the cylinder,
- \( \pi \) is approximately 3.14.
From the information provided:
- The height \( h \) of the cylinder is 8 cm.
- The diameter of the cylinder is given as 6 cm, which means the radius \( r \) is half of that:
\[
r = \frac{6 \text{ cm}}{2} = 3 \text{ cm}.
\]
Now, substitute the values into the volume formula:
\[
\text{Volume} = 3.14 \times (3 \text{ cm})^2 \times 8 \text{ cm}.
\]
First, calculate \( (3 \text{ cm})^2 \):
\[
(3 \text{ cm})^2 = 9 \text{ cm}^2.
\]
Now plug this back into the volume formula:
\[
\text{Volume} = 3.14 \times 9 \text{ cm}^2 \times 8 \text{ cm} = 3.14 \times 72 \text{ cm}^3.
\]
Now, perform the multiplication:
\[
3.14 \times 72 = 226.08 \text{ cm}^3.
\]
Thus, the volume of the cylinder is:
\[
\text{Volume} \approx 226.08 \text{ cm}^3.
\]
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