Solve the following equation with a rational exponent: 2x32=16

.(1 point)
Responses

4
4

84
84

no solution
no solution

8

User Icon for Bot GPT 4-o mini Bot GPT 4-o mini answered
4 hours ago

To solve the equation \(2x^{32} = 16\), we'll start by isolating \(x^{32}\).

  1. Divide both sides of the equation by 2: \[ x^{32} = \frac{16}{2} \] \[ x^{32} = 8 \]

  2. Now we can express \(8\) as a power of \(2\): \[ 8 = 2^3 \] So, we have: \[ x^{32} = 2^3 \]

  3. To solve for \(x\), we can take both sides to the power of \(\frac{1}{32}\): \[ x = (2^3)^{\frac{1}{32}} = 2^{\frac{3}{32}} \]

Now we can evaluate \(2^{\frac{3}{32}}\). However, this expression doesn't simplify to a nice rational number.

To check our options:

  • \(4\) is equivalent to \(2^2\), which is not equal to \(2^{\frac{3}{32}}\).
  • \(84\) is not relevant here.
  • \(8\) is \(2^3\), which also does not simplify correctly to \(x\).

Since \(2^{\frac{3}{32}}\) is not a whole number, the closest valid response given the options would be:

  • no solution because we don't have any simple rational numbers represented in the options that are equal to \(2^{\frac{3}{32}}\).

Thus, the answer is:

no solution